(B) According to Brewster's law,when light is incident at the polarizing angle (Brewster's angle,$i_p$),the reflected light is completely plane-polari

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(B) According to Brewster's law,when light is incident at the polarizing angle (Brewster's angle,$i_p$),the reflected light is completely plane-polarized.In this case,the angle of incidence is given as $i = 60^{\circ}$,which is the polarizing angle.Brewster's law states that the refractive index $\mu$ of the medium is given by $\mu = \tan(i_p)$.Substituting the given value: $\mu = \tan(60^{\circ})$.Since $\tan(60^{\circ}) = \sqrt{3}$,the refractive index of the glass is $\mu = \sqrt{3}$.

Class 12 Physics Wave Optics Brewster's Law and Other methods of polarisation

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$A$ beam of light strikes a piece of glass at an angle of incidence of $60^{\circ}$ and the reflected beam is completely plane-polarized. The refractive index of glass is

A
$1.5$
B
$\sqrt{3}$
C
$\sqrt{2}$
D
$\frac{3}{2}$

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Brewster's Law and Other methods of polarisation

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$A$ ray of light is incident on the surface of a glass plate of refractive index $\sqrt{3}$ at the polarising angle. The angle of refraction of the ray is (in $^{\circ}$)

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When unpolarized light is incident at an angle of $60^{\circ}$ on a transparent medium from air,the reflected ray is completely polarized. The angle of refraction in the medium is (in $^{\circ}$)

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The angle of incidence of light falling on a material is $60^{\circ}$,and the reflected light is completely polarized. The speed of the refracted ray inside the material (in $m/s$) is:

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$A$ beam of light strikes a piece of glass at an angle of incidence of $60^{\circ}$ and the reflected beam is completely plane-polarized. The refractive index of glass is

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The polarising angle for a transparent medium is $\theta$,and $v$ is the speed of light in that medium. Then the relation between $\theta$ and $v$ is (where $c$ is the velocity of light in air).

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